OK here is hopefully the correct answer.
(−2)3−3(−2)2⋅2√3i+3(−2)(2√3i)2−(2√3i)3=
(−2)3−3(−2)2⋅2√3i−3⋅2(2√3i)2−(2√3i)3=
−8−(−2)2⋅3⋅2√3i−3⋅2(2√3i)2−(2√3i)3=
3(−2)2⋅2√3i=
22⋅3⋅2√3i=
24√3i=
−8+72=
64
Because you are looking for the absulate value the answer is
64.
Another way would be to evaluate |−2−2i√3|3. We have: √(−2)2+(−2√3)2=√4+4⋅3=√16=4⟹43=64 ◼