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Ohm's law states that \(V = I R\) for a simple circuit, where \(V \) is the total voltage, \(I\) is the amount of current running through the resistor and \(R\) is the resistance of the resistor. If \(I = 40\) amperes when \(R = 3\) ohms, find the amount of current (in amperes) when the resistor has a resistance of  \(20\)ohms. Assume voltage remains constant.

Logic  Sep 10, 2018
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V=IR; I=40A; R=3Ω
V=40*3=120V

120V=I*R; this time, R=20Ω
120V=I*20Ω
I=120/20=6A

Guest Sep 10, 2018

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