+0  
 
+1
40
2
avatar+946 

I know the formula is T = rFsin(theta) 

So: T = (0.3)(5)sin(67) 

T = 1.4 Nm 

But then what do I do?

Julius  May 18, 2018
 #1
avatar+26716 
0

You have used 5 N instead of 50 N!  Apart from that you have done the calculation correctly.  (Your torque, T, should be 10 times larger than your 1.4 Nm).

Alan  May 18, 2018
 #2
avatar+946 
0

Oh, so it would be 13.8 Nm as the final answer? It seems like it has more to it then that :\

Julius  May 18, 2018

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