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Let \(\triangle ABC\) have side lengths \(AB=13\), \(AC=14\), and \(BC=15\). There are two circles located inside \(\angle BAC\) which are tangent to rays \(\overline{AB}\), \(\overline{AC}\), and segment \(\overline{BC}\). Compute the distance between the centers of these two circles.

 Mar 26, 2019
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The distance between the centers is 14*sqrt(2).

 Dec 1, 2019

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