What is the greatest integer value of x for which 6x^2 + x - 2 < 0?
We will use the quadratic formula:
(-b+-sqrt(b^2-4ac))/2a
(-1+-sqrt(1+48))/12
=(-1+-7)/12
x=1/2
x=-2/3
Since 1/2 is greater, the answer will be 1/2.
Hope this helped!
This will factor to ( 3x + 2 )( 2x – 1 )
So you get 3x = –2 therefore x = –2/3
and you get 2x = +1 therefore x = +1/2
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+2095 
