#1**+2 **

When the equation of a circle is written in this form:

(x – h)^{2} + (y – k)^{2} = r^{2}

The center of the circle is located at the point (h, k) and r is the radius of the circle.

Based on the picture, it looks like the center is (3, -2) and the radius is 3.

So, the equation of this circle is:

(x – 3)^{2} + (y – (-2))^{2} = 3^{2}

**(x – 3) ^{2} + (y + 2)^{2} = 9** which is the second option

hectictar
Apr 3, 2017

#1**+2 **

Best Answer

When the equation of a circle is written in this form:

(x – h)^{2} + (y – k)^{2} = r^{2}

The center of the circle is located at the point (h, k) and r is the radius of the circle.

Based on the picture, it looks like the center is (3, -2) and the radius is 3.

So, the equation of this circle is:

(x – 3)^{2} + (y – (-2))^{2} = 3^{2}

**(x – 3) ^{2} + (y + 2)^{2} = 9** which is the second option

hectictar
Apr 3, 2017