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If a and b are integers, such that a does not equal 0 and b doe not  equal 0 and  and the quares of a and b have at most two digits, what is the greatest possible difference between the squares of  a and b

 Jun 21, 2020
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the solution is

 

 

 

so the max a or b's square is 81(9x9)

 

and the least is 1 (1x1)

 

81-1=80

 Jun 21, 2020

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