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Complex numbers are often used when dealing with alternating current (AC) circuits. In the equation $V = IZ$, $V$ is voltage, $I$ is current, and $Z$ is a value known as impedance. If $V = 1-i$ and $Z=1+3i$, find $I$. Express your answer as a complex number in the form $a+bi$, where $a$ and $b$ are real numbers.

 Jun 20, 2019

Best Answer 

 #1
avatar+91 
+2

So, we can plug the variables into the equation. 

 

\(1- i = (1+3i) I.\)

 

We divide 1 + 3i on both sides to get:

 

\(\frac{1-i}{1+3i} = I\)

 

Then we multiply 1-3i on the numerator and the denominator of the left side to get:

\(-\frac12-i\).

So, \(I = -\frac12-i\)

.
 Jun 20, 2019
 #1
avatar+91 
+2
Best Answer

So, we can plug the variables into the equation. 

 

\(1- i = (1+3i) I.\)

 

We divide 1 + 3i on both sides to get:

 

\(\frac{1-i}{1+3i} = I\)

 

Then we multiply 1-3i on the numerator and the denominator of the left side to get:

\(-\frac12-i\).

So, \(I = -\frac12-i\)

Pushy Jun 20, 2019
 #2
avatar+109347 
0

Good job  !!!!

 

 

cool cool  cool

CPhill  Jun 20, 2019
 #3
avatar+91 
+1

Thanks :)

Pushy  Jun 20, 2019
 #5
avatar
0

Wait is this in the correct format?

 Jun 21, 2019

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