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An arithmetic sequence begins: 3,8,13,18...

what is the 61st term of the sequence?

 

I don't really understand how you can get this sequence...

 May 13, 2023
 #1
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The 61st term is 3 + 61*5 = 308.

 May 13, 2023
 #3
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You included the first term while adding, keep in mind that you only start to add 5 from the second term onwards. #2 has it correct, where the general formula for the nth term of an arithmetic sequence with first term a and common difference d would be a + (n-1)*d.

abk3382  May 13, 2023
 #2
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An arithmetic sequence begins: 3,8,13,18...  

what is the 61st term of the sequence?  

 

The sequence is, you add 5 to the previous number. 

 

2nd term,  add 1 x 5 to 3  

3rd term,  add 2 x 5 to 3  

4th term,  add 3 x 5 to 3  

 

So you see, for each nth term, add (n – 1) x 5 to 3  

 

For the 61st term, add (61 – 1) * 5 to 3  

 

                                     (60 * 5) + 3  =  303  

.

 May 13, 2023
 #4
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0

Thank you so much!!!

I get it now

Guest May 13, 2023
 #5
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Thank you so much!!!

 May 13, 2023

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