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An arithmetic sequence begins: 3,8,13,18...  

what is the 61st term of the sequence?  

The sequence is, you add 5 to the previous number. 

2^nd term,  add 1 x 5 to 3  

3^rd term,  add 2 x 5 to 3  

4^th term,  add 3 x 5 to 3  

So you see, for each n^th term, add (n – 1) x 5 to 3  

For the 61st term, add (61 – 1) * 5 to 3  

                                     (60 * 5) + 3  =  303  

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Thank you so much!!!