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The longer base of an isosceles trapezoid is a chord of a circle, and the shorter base is tangent to the circle. If the length of one leg is 5 and the lengths of the bases are 24 and 18, find the area of the circle.

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$h_{Tr}=\sqrt{5^2-3^2}=4\\ r^2=(r-h)^2+12^2\\ r^2=(r-4)^2+144=16-8r+r^2+144\\ 8r=160\\ \color{blue}r=20$

$A=\pi r^2=\pi \cdot20^2\\ \color{blue} A= 1256.637$

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