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# help !!!!!

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Find the slope-intercept equation of the line passing through the points (–3, –5) and
(6, –2).

Jun 27, 2021

#1
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Remember how to find the slope between two points  ?    ( y1-y2) /(x1-x2) = m = slope = 1/3

y = mx + b

y = 1/3 x + b     sub in one of the points to calculate 'b'

-2 = 1/3 (6) + b       then b = -4

y = 1/3 x -4

Jun 27, 2021
#2
+502
+1

The slope intercept form is: $$y=mx+b$$

First you need to find the slope (m). $$m=\frac{y_2−y_1}{x_2-x_1}.$$

$$m=\frac{−2−\left(−5\right)}{6−\left(−3\right)}$$

$$m=\frac13$$

Next, you find the y-intercept, or b. You can plug in any of the 2 points like this: $$y=\frac13x+b$$

$$-2=\frac13\cdot6+b$$

$$2+b=-2$$

$$b=-4$$

So our final answer is $$y=\frac13x-4$$

(I just wanted to make ElectricPavlov's solution more clear)

Jun 29, 2021