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Find the slope-intercept equation of the line passing through the points (–3, –5) and
(6, –2).

 Jun 27, 2021
 #1
avatar+35057 
+2

Remember how to find the slope between two points  ?    ( y1-y2) /(x1-x2) = m = slope = 1/3

 

y = mx + b

y = 1/3 x + b     sub in one of the points to calculate 'b'

-2 = 1/3 (6) + b       then b = -4

 

y = 1/3 x -4

 Jun 27, 2021
 #2
avatar+502 
+1

The slope intercept form is: \(y=mx+b\)

 

 

 

First you need to find the slope (m). \(m=\frac{y_2−y_1}{x_2-x_1}.\)

\(m=\frac{−2−\left(−5\right)}{6−\left(−3\right)}\)

\(m=\frac13\)

 

 

Next, you find the y-intercept, or b. You can plug in any of the 2 points like this: \(y=\frac13x+b\)

\(-2=\frac13\cdot6+b\)

\(2+b=-2\)

\(b=-4\)

 

 

 

So our final answer is \(y=\frac13x-4\)

 

 

 

 

 

(I just wanted to make ElectricPavlov's solution more clear)

 Jun 29, 2021

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