What is the sum of the units digits of all the multiples of 3 between 0 and 50?
From 1 to 30, there are 10 multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27, and 30. The sum of the units digits is 3+6+9+2+5+8+1+4+7+0 = 45.
Since the digits go up to 50, not 60, we stop the next list of addents up to 18. 3+6+9+2+5+8 = 33. 33+45 = \(\boxed{78}\).
You could also just use brute force and add them all up.