What ordered pair is a solution to this equation?
𝑦 = −𝑥 + 10
A line passes through (1,6) and (4,4)
What is the slope of the line?
Point (2,10); Slope 4. Write an equation for the line?
+9481 To find an ordered pair, pick any number you want, plug it into the equation for x or y , and solve for the other variable. I pick 0 for x.
y = -x + 10 = -0 + 10 = 10
When x = 0 , y = 10 . So an ordered pair is (0, 10) .
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slope = \(\frac{\text{change in y}}{\text{change in x}}\,=\,\frac{y_2-y_1}{x_2-x_1}\,=\,\frac{4-6}{4-1}\,=\,-\frac{2}{3}\)
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The point slope form of the line is:
y - 10 = 4(x - 2) This equation is correct as it is, but do you need it in slope-intercept form?
+9481 To find an ordered pair, pick any number you want, plug it into the equation for x or y , and solve for the other variable. I pick 0 for x.
y = -x + 10 = -0 + 10 = 10
When x = 0 , y = 10 . So an ordered pair is (0, 10) .
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slope = \(\frac{\text{change in y}}{\text{change in x}}\,=\,\frac{y_2-y_1}{x_2-x_1}\,=\,\frac{4-6}{4-1}\,=\,-\frac{2}{3}\)
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The point slope form of the line is:
y - 10 = 4(x - 2) This equation is correct as it is, but do you need it in slope-intercept form?
We need to get y - 10 = 4(x - 2) into the form: y = mx + b .
