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Sans is mad at you. If there's a 1/6 chance he'll throw a bone at you, and a 1/12 chance you'll be able to dodge it, what is the probability of Sans throwing 79 bones at you, and you dodging 60 or more of them?

 

This one's really hard... Help?

 Nov 6, 2020
 #1
avatar+93 
+2

Here's my best attempt at this question... hope I get it!

 

We know the probability of Sans throwing 79 bones is $\left(\frac{1}{6}\right)^{79}$
We also know that the probability of you dodging 60 or more of them is $\left(\frac{1}{12}\right)^{60}$
But he can choose which 60 to dodge in $\binom{79}{60}$
Therefore the answer is: (Lol you can just plug that into a calculator, but I'm not gonna do it since this page isn't saved) \[\left(\frac{1}{6}\right)^{79}*\binom{79}{60}*\left(\frac{1}{12}\right)^{60}\]

 

Hope this helped! angel

 Nov 6, 2020
 #2
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Oh wow that's correct! Thank you!

 

BTW How did you see this question so fast though? You answered it like 3 minutes after I posted it!

Guest Nov 6, 2020
 #3
avatar+93 
+1

Lol I just happened to be on this page when you posted this.

ETERNITY  Nov 6, 2020

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