ABCD is a square with side length 2. M is the midpoint of BC, and N is the midpoint of CD. Find the area of quadrilateral MNDB.
the area is 1 1/2 or 1.5 becuase you are basicly divideing it into th halvs of the 4 squares that you made so I got 1/2 or 0.5 and you subtract 1 of those triangles and 2 of the squares so the area is 4-2-0.5=1.5=1 1/2=3/2
Draw the diagonal DB.
1) Find the area of triangle(CDB) = ½·2·2 = 2
2) Find the area of triangle(CNM) = ½·1·1 = ½
3) Subtract the area of triangle(CNM) from triangle(CDB): 2 - ½ = 1½
This is the area of quadrilateral(NMBD).
