Find the solutions of the equation \(x^2 + 36 = 0.\)
x^2 + 36 = 0
x^2 = -36 take both roots
x = ±√[-36]
x = ±√[-1* 36]
x = ±i√36
x = ± 6i
( x + 6i ) ( x - 6i ) = 0
\(x = \pm\ 6i\)
Edit: For anyone who cares enough to look at my post and wants to know how to do the plus-minus sign in latex, it is \pm . On websites like AoPS, it is $\pm$ .
Whenever you have an equation in this form, try to isolate x, then take the square roots of both sides
This is called the square roots method.
Yeah by still it's a different way... I personally like CPhills way, but I like presenting 2 sides, which is why I posted on CPhills answer.