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Find the solutions of the equation \(x^2 + 36 = 0.\)

 Jul 2, 2019
 #1
avatar+111438 
+2

x^2 + 36  = 0

 

x^2  = -36     take both roots

 

x = ±√[-36]

 

x = ±√[-1* 36]

 

x = ±i√36

 

x = ± 6i

 

 

cool cool cool

 Jul 2, 2019
 #2
avatar+1709 
+9

( x + 6i ) ( x - 6i ) = 0

 

\(x = \pm\ 6i\)

 

-\(tommarvoloriddle\)

 

 

Edit: For anyone who cares enough to look at my post and wants to know how to do the plus-minus sign in latex, it is \pm . On websites like AoPS, it is $\pm$   .

tommarvoloriddle  Jul 2, 2019
edited by tommarvoloriddle  Jul 2, 2019
 #3
avatar+2856 
+2

Whenever you have an equation in this form, try to isolate x, then take the square roots of both sides

 

This is called the square roots method.

CalculatorUser  Jul 2, 2019
 #4
avatar+1709 
+9

Yeah by still it's a different way... I personally like CPhills way, but I like presenting 2 sides, which is why I posted on CPhills answer.

 

-\(tommarvoloriddle\)

tommarvoloriddle  Jul 3, 2019

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