The size of the perimeter of the square ABCD is equal to 100 cm. The length of the segment MN is equal to 5 cm and the triangle MNC is isosceles. Find the area of the pentagon ABNMD.
Right scalene triangle.
Sides: a = 3.536 b = 3.536 c = 5
Area: T = 6.25
Perimeter: p = 12.071
Semiperimeter: s = 6.036
Angle ∠ A = α = 45° = 0.785 rad
Angle ∠ B = β = 45° = 0.785 rad
Angle ∠ C = γ = 90° = 1.571 rad
Area of the square - area of the triangle =100 - 6.25 =93.75 cm^2 - area of the pentagon ABNMD
