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The size of the perimeter of the square ABCD is equal to 100 cm. The length of the segment MN is equal to 5 cm and the triangle MNC is isosceles. Find the area of the pentagon ABNMD.

 

 Jan 5, 2020
 #1
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Right scalene triangle.

Sides: a = 3.536   b = 3.536   c = 5

Area: T = 6.25
Perimeter: p = 12.071
Semiperimeter: s = 6.036

Angle ∠ A = α = 45° = 0.785 rad
Angle ∠ B = β = 45° = 0.785 rad
Angle ∠ C = γ = 90° = 1.571 rad

 

Area of the square - area of the triangle =100 - 6.25 =93.75 cm^2 - area of the pentagon ABNMD

 Jan 5, 2020
 #3
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The perimeter is the continuous line forming the boundary of a closed geometric figure.

Guest Jan 6, 2020
 #2
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Square side  AB = 100/4     AB = 25cm

Square area  As = 25²        As = 625cm²

Triangle area    At = [(sin45° * 5)²]/2        At = 6.25cm²

Area of  ABNMD = As - At            ABNMD = 618.75 cm²     indecision

 Jan 6, 2020

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