+0  
 
0
35
1
avatar+199 

A cook has 10 red peppers and 5 green peppers. If the cook selects 6 peppers at random, what is the probability that he selects at least 4 green peppers? Express your answer as a common fraction.

Lightning  Apr 28, 2018
Sort: 

1+0 Answers

 #1
avatar+2592 
+2

Solution:

We can count the number of ways to choose a group of 4 green and 2 red peppers and the number of ways to choose 5 green and 1 red peppers. These are \(\binom{5}{4}\binom{10}{2}=5\cdot45=225 \) and \(\binom{5}{5}\binom{10}{1}=10\). The total number of ways the cook can choose peppers is \(\binom{15}{6}=5005\). Therefore, the probability that out of six randomly chosen peppers at least four will be green is \(\frac{235}{5005}=\boxed{\frac{47}{1001}}\).

 

smileysmiley

tertre  Apr 28, 2018

24 Online Users

avatar
avatar
New Privacy Policy (May 2018)
We use cookies to personalise content and ads, to provide social media features and to analyse our traffic. We also share information about your use of our site with our social media, advertising and analytics partners.  Privacy Policy