+0  
 
0
71
1
avatar+339 

A cook has 10 red peppers and 5 green peppers. If the cook selects 6 peppers at random, what is the probability that he selects at least 4 green peppers? Express your answer as a common fraction.

Lightning  Apr 28, 2018
 #1
avatar+2764 
+2

Solution:

We can count the number of ways to choose a group of 4 green and 2 red peppers and the number of ways to choose 5 green and 1 red peppers. These are \(\binom{5}{4}\binom{10}{2}=5\cdot45=225 \) and \(\binom{5}{5}\binom{10}{1}=10\). The total number of ways the cook can choose peppers is \(\binom{15}{6}=5005\). Therefore, the probability that out of six randomly chosen peppers at least four will be green is \(\frac{235}{5005}=\boxed{\frac{47}{1001}}\).

 

smileysmiley

tertre  Apr 28, 2018

22 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.