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When x^4+6x^3-ax^2-45x-15 is divided by x^2-x-6 the remainder is 3. What is a?

 Nov 25, 2020
 #1
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We can write \(x^4+6x^3-ax^2-45x-15=q(x)(x^2-x-6)+3\). Factoring \(x^2-x-6\) gives \((x-3)(x+2)\). So what significant numbers can you plug into the first equation to get the answer? Can you take it from here?

 Nov 25, 2020
 #2
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Yes thank you for your help!

Guest Nov 26, 2020

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