The sum of two positive numbers is 4 and the sum of their squares is 28. What are the two numbers?
x+y = 4 can only be 1 3 or 2 2 which would not satisfy the next equation
x^2 + y^2 = 28 Are you sure they are both positive?
So sum of two positive numbers is 4, and sum of their squares is 28.
Only possible numbers are 1 and 3, and 2 and 2. 0, 4 wouldn't work because square of 0 is 0.
1 + 3 = 4
1^2 = 1
3^2 = 9
1+9 = 10.
(1,3) doesn't work.
2 + 2 = 4.
2^2 = 4
2^2 = 4
4+4 = 8.
(2,2) doesn't work.
Nothing positive works... so unless they're negative, the problem has no answer.