We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.


A rhombus with area 840 has a diagonal of length 40 . What is its side length?

 Apr 21, 2019

We have \(\frac{pq}{2}\), as \(p\) and \(q\) are the two diagonals. Thus, we have \(\frac{40*q}{2}=840\), and \(40q=1680, q=42.\)


Now, we have four right triangles by drawing the two diagonals. If you see closer, we can use the Pythagorean Theorem, to find the side length, which is \(\sqrt{20^2+21^2}=\boxed{29}.\)

 Apr 21, 2019

To solve this problem, use the formula to find the side length of a rhombus. This is because we use the formula  \(a = \sqrt{{p}^{2}+(4*{a/p}^{2})}*1/2\)

in which a is the area and p is the diagonal. After the evaluation, we get a total of 29.



 Apr 21, 2019

8 Online Users