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# help

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A truncated cone has horizontal bases with radii 18 and 2. A sphere is tangent to the top, bottom, and lateral surface of the truncated cone. What is the radius of the sphere?

Dec 23, 2018

#1
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The radius is $$\boxed{6}$$.

- PM

Dec 24, 2018
#2
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Consider a trapezoidal (label it ABCD as follows) cross-section of the truncate cone along a diameter of the bases:

image here.

Above, E, F, and G are points of tangency. By the Two Tangent Theorem, BF = BE = 18 and CF = CG = 2, so BC = 20.

We draw H such that it is the foot of the altitude  Segment HD to Segment AB:

image here.

By the Pythagorean Theorem, $$r = \dfrac{DH}{2} = \dfrac{\sqrt{(20)^2 - (16)^2}}{2} = \boxed{6}$$.

Hope this helps,

- PM

PartialMathematician  Dec 24, 2018
#3
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If the first solution confuses you, here is a second solution.

Create a trapezoid with inscribed circle O exactly like in the solution above, and extend lines AD and BC from the solution above and label the point at where they meet H. Because $$\frac{\overline{GC}}{\overline{BE}} = \frac{1}{9}$$, $$\frac{\overline{HG}}{\overline{HE}} = \frac{1}{9}$$. Let $$\overline{HG} = x$$ and $$\overline{GE} = 8x$$.

Because these are radii, $$\overline{GO} = \overline{OE} = \overline{OF} = 4x$$. $$\overline{OF} \perp \overline{BH}$$ , so $$\overline{OF}^2 + \overline{FH}^2 = \overline{OH}^2$$. Plugging in, we get $$4x^2 + \overline{FH}^2 = 5x^2$$, so $$\overline{FH} = 3x$$.Triangles OFH and BEH are similar, so $$\frac{\overline{OF}}{\overline{BE}} = \frac{\overline{FH}}{\overline{EH}}$$, which gives us $$\frac{4x}{18} = \frac{3x}{9x}$$. Solving for x, we get $$x = 1.5$$ and $$4x = \boxed{6}$$.

Hope this helps,

- PM

PartialMathematician  Dec 24, 2018
#4
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https://artofproblemsolving.com/wiki/index.php/2004_AMC_12B_Problems/Problem_19

Nothing new here, you’ve plagiarized many times before.

Is this the only way you can correctly answer the questions?

You’ve implied others have plagiarized, but you blatantly do it yourself, so you are not only a plagiarizer you are a hypocrite!

Why are you here?

Dec 24, 2018
#5
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in the response below, you didn't even spell bs correctly...

PartialMathematician  Dec 24, 2018
edited by PartialMathematician  Dec 24, 2018
#6
+1

You are full of bulllshit!

You are one of the biggest bullshiters to join this forum.

Did you come here to practice your bulllshitting skills?

Guest Dec 24, 2018
#7
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Considering BS should be part of your name, it’s not a surprise you are familiar with the word and its correct spelling.

It seems that you are better at spelling than math, anyway.

Guest Dec 24, 2018