A bag contains 8 white and 3 red balls.if two are drawn at random without replacement,find the probability that (1) both are white (2) both are red (3) one is of each color

Guest Mar 8, 2020

#1**+1 **

You might have to check this for me. Idk if this is correct:

(1) There are 11 balls in total, with 8 white and 3 red.

First ball: You have a 8/11 chance of the first ball being white, and a 3/11 chance of it being red.

Second ball: This depends on what you drew on the first ball. If you drew a white first, you now have a 7/10 chance of getting white.

Total probability for both white: **8/11 * 7/10 (since both are independent events) = 28/55.**

(2) There are 11 balls in total, with 8 white and 3 red.

First ball: You have a 3/11 chance of being red.

Second ball: If you drew red the first time, you now have a 2/10 chance of it being red.

Total probability for both red: **3/11 * 2/10 = 3/55**

(3) I don't really know how to do this, can someone solve this?

AnimalMaster Mar 8, 2020