A bag contains 8 white and 3 red balls.if two are drawn at random without replacement,find the probability that (1) both are white (2) both are red (3) one is of each color
You might have to check this for me. Idk if this is correct:
(1) There are 11 balls in total, with 8 white and 3 red.
First ball: You have a 8/11 chance of the first ball being white, and a 3/11 chance of it being red.
Second ball: This depends on what you drew on the first ball. If you drew a white first, you now have a 7/10 chance of getting white.
Total probability for both white: 8/11 * 7/10 (since both are independent events) = 28/55.
(2) There are 11 balls in total, with 8 white and 3 red.
First ball: You have a 3/11 chance of being red.
Second ball: If you drew red the first time, you now have a 2/10 chance of it being red.
Total probability for both red: 3/11 * 2/10 = 3/55
(3) I don't really know how to do this, can someone solve this?