Assume that when adults with smartphones are randomly selected, 61% use them in meetings or classes. If 8 adult smartphone users are randomly selected, find the probability that exactly 3 of them use their smartphones in meetings or classes
+220 Thanks for the A2A. I'm going to explain this very briefly.
61% is 61/100 in fraction form. Now, we can see the probability of just 1 case.
"find the probability that exactly 3 of them use their smartphones in meetings or classes". We can do \(\frac{61^3*39^5}{{100}^{8}}\) and get approximately .002.
However, there are many cases so we will have to put in values for the combination formula.
After you substitute, you will get \(\frac{8!}{5!*3!}\). That is a total of 56 cases.
Multiply .00204 and 56. The answer in decimal form is .11424.
In percent form, it is 11.424%.
Cheers!
