Compute the sum \(\frac{1}{\sqrt{100} + \sqrt{102}} + \frac{1}{\sqrt{102} + \sqrt{104}} + \frac{1}{\sqrt{104}+\sqrt{106}} + \cdots + \frac{1}{\sqrt{9998} + \sqrt{10000}}. \)Just give me a hint. Thank you!
Tell me if you need more help. :))
(a+b)(a-b) = a^2-b^2
=^._.^=
Also, welcome to web2.0calc :DDDD
TYSM, I got the answer 45. Also thanks for welcoming me.
YAYY. :))
(sqrt(100)-sqrt(102)+sqrt(102)-sqrt(104)...sqrt(9998)-sqrt(10000))/-2
Everything cancels out. :DDD
(10-100)/-2=45
+180 
