In the figure below, ABCD is a parallelogram, AD = 18 and DC = 27. Segments EG (which is a repeating decimal) and FH (which is a repeating decimal) are perpendicular to sides of the parallelogram as shown, and EG = 16. Determine FH.
Since DC can be considered as one base of parallelogram ABCD and EG is the height drawn to this base.....the area is DC * EG = 27 * 16 = 432 units^2
But BC can be considered as another base and FH is a height drawn to this base....and since the area is constant......we have that
432 = BC * FH but AD = BC = 18 ....so....
432 = 18 * FH divide both sides by 18
24 = FH