#1**+9 **

Best Answer

Simplify the following:

1/((2 x^4)/y^3)

Multiply the numerator of 1/((2 x^4)/y^3) by the reciprocal of the denominator. 1/((2 x^4)/y^3) = (1 y^3)/(2 x^4):

**Answer: | y^3 / (2x^4)**

Guest Jan 23, 2016

#3**+5 **

First start with 2x^4 y^-3 this equals (2x^4) / y^3 now invert them due to the - 1 power

y^3/(2x^4)

Guest Jan 23, 2016

#4**0 **

#3. Shorter way of doing it. :D. Shorter = better?

Sorry, I seem to be a bit hyper.

Hayley1 Jan 23, 2016

#5**0 **

Hi Quazw...

What is (2x⁴y⁻³)⁻¹?

**This is the easiest way.**

1) write it as a fraction

\(\frac{(2x^4y^{-3})^{-1}}{1}\)

2) Anything that is raised to a negative number gets swapped to the other side of the fraction line and the negaive becomes positive.

[NOTE: negative numbers (coefficients) are NOT negative indices but there are no negative numbers here so I don't need to worry.]

\(=\frac{1}{1*(2x^4y^{-3})^{+1}} \qquad \mbox{There was nothing left on the top so I put a 1 there!}\\~\\ =\frac{1}{2x^4y^{-3}} \\~\\ =\frac{y^{+3}}{2x^4} \\~\\ =\frac{y^{3}}{2x^4} \\~\\ \)

.Melody Jan 24, 2016