Draw:
- An isosceles triangle that has a vertex angle of 120.
- If you draw from Q to the midpoint of PR, you can create two 30-60-90 triangles.
Solve:
Knowing that the triangles are 30-60-90 with the hypotenuse given, can you find the height and base of the triangle and solve?
AnExtremelyLongName:
This is an isosceles triangle, with angles 120, 30, and 30. It says in the question that angle PQR is 120 degrees, which makes the other 30 degrees.
Yes I know. What are you implying? There are multiple ways to solve this.
- The easiest (in my opinion) is my first post.
- Another method is to apply the law of cosines to solve for the last missing side, then use Heron's Formula to calculate the area
There may be more!