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# Help

0
105
5

2x - 7 (is less than or equal to sign) 3x + 10

Feb 4, 2019

#1
+18965
+1

2x-7 <= 3x+10     subtract 2x from both sides

-7 <= x +10          subtract 10 from each side

-17 <= x           or    x >= -17

Feb 4, 2019
#3
0

thx, i was confused i almost subtracted 3x from 2x and that would have given something is less than or equal to 17

Guest Feb 4, 2019
#4
+18965
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That is OK......but you have to go a bit further to solve for 'x'

2x-7 <= 3x+10      subtract 3x from both sides

-x <= 17                  NOW you have to MULTIPLY by -1     this reverses the < sign

ElectricPavlov  Feb 4, 2019
#5
0

really? that is crazy. math is so cool.

Guest Feb 4, 2019
#2
+79
+2

If $$2x-7 \leq 3x+10$$, then we can subtract 10 to both sides. Then, subtract 2x from both sides. You will get that $$x\geq -17$$, which is your solution.

Feb 4, 2019