2x-7 <= 3x+10 subtract 2x from both sides
-7 <= x +10 subtract 10 from each side
-17 <= x or x >= -17
thx, i was confused i almost subtracted 3x from 2x and that would have given something is less than or equal to 17
That is OK......but you have to go a bit further to solve for 'x'
2x-7 <= 3x+10 subtract 3x from both sides
-x <= 17 NOW you have to MULTIPLY by -1 this reverses the < sign
x>= -17 Same answer......