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2x - 7 (is less than or equal to sign) 3x + 10

 Feb 4, 2019
 #1
avatar+18293 
+2

2x-7 <= 3x+10     subtract 2x from both sides

-7 <= x +10          subtract 10 from each side

-17 <= x           or    x >= -17

 Feb 4, 2019
 #3
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thx, i was confused i almost subtracted 3x from 2x and that would have given something is less than or equal to 17

Guest Feb 4, 2019
 #4
avatar+18293 
+1

That is OK......but you have to go a bit further to solve for 'x'

 

2x-7 <= 3x+10      subtract 3x from both sides

-x <= 17                  NOW you have to MULTIPLY by -1     this reverses the < sign

x>= -17         Same answer......

ElectricPavlov  Feb 4, 2019
 #5
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really? that is crazy. math is so cool.

Guest Feb 4, 2019
 #2
avatar+79 
+2

If \(2x-7 \leq 3x+10\), then we can subtract 10 to both sides. Then, subtract 2x from both sides. You will get that \(x\geq -17\), which is your solution.

 Feb 4, 2019

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