#1**+3 **

Hey there, guest!

Since they mentioned that BE is congruent to BC, that means that triangle BCE is isosceles. And since it is isosceles, angle C is equal to angle E. So, angle E = 35 degrees.

From here, everything is much easier. Since we know angle DFB is 102, that means angle DFE is 180-102=78 degrees (since EB is a straight line).

We also know angle EDF is 180-35-78=67 degrees (using the triangle theorem).

Now, I think I've done enough for you. I think you can solve the rest on your own!

You got this!

:)

lokiisnotdead Apr 27, 2020

#2**+3 **

Another way:

Working off of lokiisnotdead, we know that triangle \(BCE\) is isosceles. That means angle EBC is 180 - 35 * 2 = 110

- By supplements we know that FBA is 180-110=70

- By supplements we know that AFB is 180-102 = 78

Now that you know two angles of triangle AFB, you can find the third angle, which is angle \(A\).

*All angles in a triangle add up to 180

AnExtremelyLongName Apr 27, 2020