Hey there, guest!
Since they mentioned that BE is congruent to BC, that means that triangle BCE is isosceles. And since it is isosceles, angle C is equal to angle E. So, angle E = 35 degrees.
From here, everything is much easier. Since we know angle DFB is 102, that means angle DFE is 180-102=78 degrees (since EB is a straight line).
We also know angle EDF is 180-35-78=67 degrees (using the triangle theorem).
Now, I think I've done enough for you. I think you can solve the rest on your own!
You got this!
Working off of lokiisnotdead, we know that triangle \(BCE\) is isosceles. That means angle EBC is 180 - 35 * 2 = 110
- By supplements we know that FBA is 180-110=70
- By supplements we know that AFB is 180-102 = 78
Now that you know two angles of triangle AFB, you can find the third angle, which is angle \(A\).
*All angles in a triangle add up to 180