how can i make a triangle with the hypotenuse of square root of 80
You need a line of length √5, and at one end of it draw a perpendicular line of length 4. Join their ends to form the hypotenuse and applying the wisdom of Pythagoras this third line will be of length √80. 😁 😁 😁
But wait! Where do you find that first line of length √5? You must construct it also—as the hypotenuse of a ∆ having base=1 and whose height=2.