+0  
 
0
32
2
avatar

Find the remainder when the sum \(2^{2} + 2^{6} + 2^{10} + 2^{14} + \cdots + 2^{110} \) is divided by 10.

 Oct 1, 2021
 #1
avatar
0

Using geometric series and mod 10, the last digit is a 6, so the remainder is 6.

 Oct 1, 2021
 #2
avatar
0

But since its divided by 10 you need the last 2 digits

Guest Oct 1, 2021

24 Online Users