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# Help

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Find the remainder when the sum \(2^{2} + 2^{6} + 2^{10} + 2^{14} + \cdots + 2^{110} \) is divided by 10.

Oct 1, 2021

#1
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Using geometric series and mod 10, the last digit is a 6, so the remainder is 6.

Oct 1, 2021
#2
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But since its divided by 10 you need the last 2 digits

Guest Oct 1, 2021