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Help.

 Jan 29, 2018
 #1
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3.

 

3√ [ 4x^2  *  3 √ [ 8x^7 ]    =

 

3√ [  4* 8  x^2  x^7 ]  =

 

3√ [ 32  x^9 ]  =                            {note that 32  = 2^5 ]

 

3√  [ 2^5 x^9 ]

 

To determine how many powers of 2 to take out and how many to leave in, we have

 

5/3   =  1  + 2/3          1 power of 2 comes out and 2 stay in

 

To determine how many powers of x come out and how many stay in, we have

 

9 / 3   =  3  powers come out      .....    so we end up with

 

 2 x^3 3√ [2^2]     =    2x^3 *  3√ 4  

 

 

 

4.

 

4√ 810

______    =      4 √ [ 810 / 2]    =  4√405   = 4 √ [ 81 * 5 ]  = 4√81   * 4√5

4√2

 

 

Note that 81  =  3^4   ....so we have...

 

4√81  * 4√ 5      =

 

4√ [ 3^4] *  4√5    =

 

To determine how many powers of 3 to take out    4/4  =  1 power of 3

 

3 4√5

 

 

cool cool cool

 Jan 29, 2018

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