#1**+2 **

a) Hint: Plus it in

\(\sqrt{5^2+12^2}\), then solve. You should get an integer as an answer

b) To do this problem, you can square both sides.

\(x^2+2xy+y^2=x^2+y^2\)

Then cancel out x^2 and y ^2

\(2xy = 0\)

Then solve

\(x*y=0\).

So when x and y multiplied together equaling 0 is when it can satisfy the original equation.

Examples: (0, 0) (10, 0) (0, 5)

Values of x and y that DO NOT satisfy the original equation is when they DO NOT multiply to 0

Examples (1, 1) (2, 3) (6, 9)

CalculatorUser Sep 30, 2019