Watermelons and mangoes are sold at a fruit stall. There were 13 more watermelons than mangoes at first. After 3/5 of the watermelons and 5/9 of the mangoes were sold, there was an equal number of each type of fruit left unsold.

a) What was the total number of fruits left unsold

b) Both the watermelons and the mangoes are sold for $3.60 each. How much money was collected from the sale of fruits?

sugabreaddoughman Jul 15, 2024

#1**+1 **

(a) let's write an equation to solve this problem.

Let's let w be the total number of watermelons and m be the total number of mangoes.

Using the problem, we have the system of equations

\(w=m+13\\ 2/5w = 4/9m\)

Subsituting out w with m from the first equation, we get

\(\frac{2}{5}(m+13) = \frac{4}{9}m\)

Solving this equation yields

\(m=117\). Since there are 13 more watermelons, then \(w=130\)

Next, let's find how many of each there were. Since \(2/5(130) = 52\), we have

\(52*2=104\)

So 104 is our final answer.

Thanks! :)

NotThatSmart Jul 15, 2024

#2**+1 **

(b) We know there were 52 watermelons and 52 mangoes remaining.

There are also 130 watermelones and 117 mangoes.

Thus, we just have

\(130-52=78\\ 117-52=65\)

Adding the two numbers up, we find that \(78+65=143\)

This means they sold a total of 143 watermelons and mangoes.

Since each cost 3.60, we have

\(3.60 *143 = 514.8\)

Thus, they collected 514.8 dollars.

Thanks! :)

NotThatSmart Jul 15, 2024