+0  
 
0
36
1
avatar+14 

\(\frac{2}{5}x= 16yw\) for some positive real numbers. If \(y\) is tripled and \(w\) is halved, by what percentage does x have to increase for the equation to be equal?

 Aug 17, 2023
edited by PurpleWasp  Aug 17, 2023
 #1
avatar
0

 

We have that 2x/5=16yw. If y is tripled and w is halved, then the new equation becomes [2x/5 = 16(3y)(w/2) = 24wy.]Dividing both sides by 5, we get [x/5 = 4wy.]Since the left side is 20% of the right side, x must be increased by 20%​.

 Aug 17, 2023

5 Online Users

avatar
avatar