+118667 Here is my best guess
Say they all go consecutive (no pairs)
5! ways to order them then each of those can go to pad 1 or pad 2.
So that is 5! 8 2^5 = 120*32 = 3840 ways
Now look at one pair.
There are 5C2=10 ways to choose the pair (ty these together with a rope so now they only count as one.
There are 4! ways to line them up now.
the three singles will each have a choice of pad that is 2^3 ways
The double obviously uses both pads but can be in either order on those pads so that is 2 ways
10 * 4! * 2^3 * 2 = 10 * 24 * 16 = 3840 ways
Now look at 2 pairs
I think that there are 5C2 * 3 /2 ways to chose these = 15 ways
there are 3! ways to line them up
there are 2^3 ways to chose the pads.
15 * 6 * 8 = 720 ways
3840+ 3840 + 720 = 8400 ways
