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please help me. I tried and coudln't figure it out.

 Mar 25, 2018

Best Answer 

 #1
avatar+7354 
+2

A)   ∠A  intercepts arc CD.

 

B)   ∠BED  intercepts arc BCD.

 

C)   The measure of an inscribed angle is half the measure of its intercepted arc. So...

       The measure of ∠BED is half the measure of arc BCD

       The measure of ∠BED   =   (1/2)(the measure of arc BCD)

       85°   =   (1/2)(the measure of arc BCD)

       2(85°)   =   the measure of arc BCD

       170°   =   the measure of arc BCD

 

D)   The measure of ∠A   =   (1/2)(the measure of arc CD)

       The measure of ∠A   =   (1/2)(128°)

       The measure of ∠A   =   64°

 

E)   The sum of all the arcs in a circle is 360° , so...

       The measure of the rest of the circle   =   360° - 82°

       The measure of the rest of the circle   =   278°

 Mar 25, 2018
 #1
avatar+7354 
+2
Best Answer

A)   ∠A  intercepts arc CD.

 

B)   ∠BED  intercepts arc BCD.

 

C)   The measure of an inscribed angle is half the measure of its intercepted arc. So...

       The measure of ∠BED is half the measure of arc BCD

       The measure of ∠BED   =   (1/2)(the measure of arc BCD)

       85°   =   (1/2)(the measure of arc BCD)

       2(85°)   =   the measure of arc BCD

       170°   =   the measure of arc BCD

 

D)   The measure of ∠A   =   (1/2)(the measure of arc CD)

       The measure of ∠A   =   (1/2)(128°)

       The measure of ∠A   =   64°

 

E)   The sum of all the arcs in a circle is 360° , so...

       The measure of the rest of the circle   =   360° - 82°

       The measure of the rest of the circle   =   278°

hectictar Mar 25, 2018

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