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Hector found four consecutive odd integers such that five times the sum of the first and the third was 22 greater than the product of and the sum of the second and the fourth. What were the integers?

 Mar 13, 2020
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make 2x+1 the middle-ish integer   the two below will be  2x -1   and 2x -3     above will be 2x +3 

 

2x -3     2x-1     2x+1      2x+3 

 

5 ( 2x-3  + 2x+1)   = 22 +  (2x-1)(2x+3)  + (2x-1 + 2x+3)   solve for 'x'

5 ( 4x-2)   = 22 + ( 4x^2 +4x-3) + (4x+2)

20x-10      = 22  + 4x^2 +8x -1

0    =    4x^2 - 12x +31                       x = hmmmmmmmm     non integer

 

can you clarify this part?  ' 22 greater than the product of and the sum of the second and the fourth'

 Mar 13, 2020

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