Hector found four consecutive odd integers such that five times the sum of the first and the third was 22 greater than the product of and the sum of the second and the fourth. What were the integers?
make 2x+1 the middle-ish integer the two below will be 2x -1 and 2x -3 above will be 2x +3
2x -3 2x-1 2x+1 2x+3
5 ( 2x-3 + 2x+1) = 22 + (2x-1)(2x+3) + (2x-1 + 2x+3) solve for 'x'
5 ( 4x-2) = 22 + ( 4x^2 +4x-3) + (4x+2)
20x-10 = 22 + 4x^2 +8x -1
0 = 4x^2 - 12x +31 x = hmmmmmmmm non integer
can you clarify this part? ' 22 greater than the product of and the sum of the second and the fourth'