+0

# help

+1
53
2

how do you solve this equation? 23*0.94^x=15

Dec 13, 2018

#1
+3580
+1

$$23(0.94)^x = 15\\ (0.94)^x = \dfrac{15}{23}\\ x\log(0.94) = \log\left(\dfrac{15}{23}\right) = \log(15)-\log(23)\\ x = \dfrac{\log(15)-\log(23)}{\log(0.94)}$$

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Dec 13, 2018

#1
+3580
+1

$$23(0.94)^x = 15\\ (0.94)^x = \dfrac{15}{23}\\ x\log(0.94) = \log\left(\dfrac{15}{23}\right) = \log(15)-\log(23)\\ x = \dfrac{\log(15)-\log(23)}{\log(0.94)}$$

Rom Dec 13, 2018
#2
0

You have to divide both sides by 23 and then calc a logaritm (log) with base 0.94 of the right side so its gonna be x=log0.94(15/23) web2.0calc doesn't have an option for any base of logarythm so you can just calc ln(15/23)/ln(0.94) and the answer won't change. By the way answer is around 6.908.

Dec 13, 2018