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Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 14 feet and a height of 19 feet. Container B has a diameter of 12 feet and a height of 20 feet. Container A is full of water and the water is pumped into Container B until Conainter B is completely full.

After the pumping is complete, what is the volume of water remaining in Container A, to the nearest tenth of a cubic foot?

 Apr 2, 2020
 #1
avatar+53 
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The percentage ≅ 48.4%

Step-by-step explanation:

* Lets revise how to find the volume of a container shaped cylinder

- The volume of any container = area of its base × its height

- The base of the cylinder is a circle, area circle = 2 π r,

  where r is the length of its radius

* In container A:

∵ r = 13 feet  , height = 13 feet

∴ Its volume = π (13)² × (13) = 2197π feet³

* In container B:

∵ r = 9 feet  , height = 14 feet

∴ Its volume = π (9)² × (14) = 1134π feet³

* So to fill container B from container A, you will take from

  container A a volume of 1134π feet³

- The volume of water left in container A = 2197π - 1134π = 1063π feet³

* To find the percentage of the water that is full after pumping

  is complete, divide the volume of water left in container A

  by the original volume of the container multiplied by 100

∴ The percentage = (1063π/2197π) × 100 = 48.3841 ≅ 48.4%

 Apr 2, 2020
 #2
avatar+1968 
+1

You can also see a similar question here that will help you solve this:

 

https://brainly.com/question/12425898

 Apr 2, 2020

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