How many liters of a 10% alcohol solution must be mixed with 30 liters of a 50% solution to get a 20% solution?
+36916 x = amount of 10%
amount of alcohol = .1x in the 30 l there is .5 (30) of alcohol
final alcohol amount will be .2 (30 + x)
sooooo
.1x + .5(30) = .2 (30 + x) Solve for 'x' the amount of 10% needed
