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How many liters of a 10% alcohol solution must be mixed with 30 liters of a 50% solution to get a 20% solution?

 Jun 10, 2020
 #1
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+1

it makes the equation ((0.1x)+30*50%)/(x+30)=0.2 to get (0.1x+15)/(x+30)=0.2 so x=90

 Jun 10, 2020
edited by jimkey17  Jun 10, 2020
 #2
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+2

x = amount of 10%

 

amount of alcohol   =   .1x         in the 30 l  there is  .5 (30) of alcohol

 

final alcohol amount will be   .2 (30 + x)

sooooo

.1x      + .5(30) =  .2 (30 + x)    Solve for 'x'   the amount of 10% needed

 Jun 10, 2020

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