A bag contains 4 Kit Kats, 3 Snicker Bars, 1 Hershey Bar. Howie chooses a candy bar at random and eats it. Then Ellen chooses a candy bar. What is the probability that Howie chooses a Kit Kat and Ellen chooses a Hershey Bar? Write your answer as a fraction in simplest form.
+538 The chance that Howie chooses a Kit Kat is \(\frac{4}{8} = \frac{1}{2}\)The chance Ellen chooses a Hershey is \(\frac{1}{7}\)Multiplying the two probabilities, we get \(\frac{1}{14}\)
