P is a point inside square ABCD such that Angle PAB = Angle PBA = 15 degrees. Find angle PCD.
Let the square side AB = 2
Let's denote the midpoints of a side AB with a letter M, and a side CD with a letter Q
MP = tan(15°) * 1 MP = 0.268
PQ = BC - MP PQ = 1.732
∠DCP => q tan(q) = PQ / [(AB)/2] q = 60°
Nice, Dragan.....!!!!
