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There were some avocados in 3 boxes, E, F and G. 30% of the number of avocados in Box E was equal to 60% of the number of avocados in Box F. The number of avocados in Box G was 60% of the total number of avocados in Box E and F. After Oscar removed 20% of the avocados in Box G, there were 88 more avocados in Box F than in Box G. In the end, how many avocados should be transferred from Box F to Box G so that the avocados in Box G would be the same as Box E?

 Apr 25, 2022
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There were some avocados in 3 boxes, E, F and G. 30% of the number of avocados in Box E was equal to 60% of the number of avocados in Box F. The number of avocados in Box G was 60% of the total number of avocados in Box E and F. After Oscar removed 20% of the avocados in Box G, there were 88 more avocados in Box F than in Box G. In the end, how many avocados should be transferred from Box F to Box G so that the avocados in Box G would be the same as Box E?

 

I do not think that this scenario is possible.

30% of the number of avocados in Box E was equal to 60% of the number of avocados in Box F

so

0.3E=0.6F

E=2F

So in the beginning there are 2 times more in box E than in box F     (And  each one has a muliple of 10)

 

G=0.6(E+F)

G=0.6(3F)

G=1.8F

 

Now 20% are removed from box G

so box G will then have    0.8*1.8F = 1.44F

 

So now

box1  (originally called box E) Box2  (originally called box F) box3  (originally called box G)
2F F 1.44F
     

 

It is clear that there are now mow avocados in the last box than in the middle one.

So there cannot be 88 more in the middle one, that is a contradiction.

 May 5, 2022

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