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Help.

 Feb 1, 2018
 #1
avatar+100483 
+1

10.

 

(8a-3)-2/3   =   8-2/3  *   (a-3)-2/3

 

Note, NSS.....

 

a-m   =   1 / am           and       ( am )n    =  am * n

 

So we have

 

 

1 / 82/3    *   a6/3

 

And  we can write

 

 

1 / 3√ [ 8 2 ]     *  a2

 

1 / 3√64  * a2  

 

1 / 4  * a2

 

 

a2 / 4

 

 

cool cool cool

 Feb 1, 2018
 #2
avatar+100483 
+1

9.  We want to multiply top/bottom by the congugate of 2 - √5 ⇒  2 + √5

 

2 + √5        (2 + √5)

_____

2 -  √5        (2 + √5)

 

 

Let's do these separately

 

( 2 + √5 )  ( 2   + √5)  =

2(2)  + 2√5 + 2√5  +  √5*√5  =

4 + 4√5 + 5 =

9 + 4√5        (1)

 

 

( 2 - √5 )  ( 2   + √5)  =

2(2)  - 2√5 + 2√5  -  √5*√5  =

4 - 5 =

-1      (2)

 

 

Put  (1)  over (2)  and we have

 

[ 9 + 4√5 ]                      -9  - 4√5

________       =     

       -1

 

 

 

 

cool cool cool

 Feb 1, 2018

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