Find a formula for the sum of the squares of the first n positive odd integers.

Guest Dec 14, 2019

#2**+1 **

EP: He/she are asking:" Formula for the sum of the squares of the **first n positive odd integers**"

OddSum = (Sum of Squares of all 2n numbers) -

(Sum of squares of first n even numbers)

= 2n*(2n+1)*(2*2n + 1)/6 - 2n(n+1)(2n+1)/3

= 2n(2n+1)/6 [4n+1 - 2(n+1)]

= n(2n+1)/3 * (2n-1)

**= n(2n+1)(2n-1)/3 - This is the formula for the sum of consecutive ODD squares.**

Guest Dec 14, 2019