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Find a formula for the sum of the squares of the first n positive odd integers.

 Dec 14, 2019
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-----------  Misread the question

See below:  cheeky

 Dec 14, 2019
edited by ElectricPavlov  Dec 14, 2019
 #2
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EP: He/she are asking:" Formula for the sum of the squares of the first n positive odd integers"

 

OddSum  = (Sum of Squares of all 2n numbers) - 
          (Sum of squares of first n even numbers)
        = 2n*(2n+1)*(2*2n + 1)/6 - 2n(n+1)(2n+1)/3
        = 2n(2n+1)/6 [4n+1 - 2(n+1)] 
        = n(2n+1)/3 * (2n-1)
        = n(2n+1)(2n-1)/3 - This is the formula for the sum of consecutive ODD squares.

 Dec 14, 2019

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