Find a formula for the sum of the squares of the first n positive odd integers.
EP: He/she are asking:" Formula for the sum of the squares of the first n positive odd integers"
OddSum = (Sum of Squares of all 2n numbers) -
(Sum of squares of first n even numbers)
= 2n*(2n+1)*(2*2n + 1)/6 - 2n(n+1)(2n+1)/3
= 2n(2n+1)/6 [4n+1 - 2(n+1)]
= n(2n+1)/3 * (2n-1)
= n(2n+1)(2n-1)/3 - This is the formula for the sum of consecutive ODD squares.
