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The half-life of carbon-14 is 5,730 years. Assuming you start with 100% of carbon-14, what is the expression for the percent, P(t), of carbon-14 that remains in an organism that is t years old and what is the percent of carbon-14 remaining (rounded to the nearest whole percent) in an organism estimated to be 30,000 years old?

Hint: The exponential equation for half-life is P(t) = A0(0.5)^t/H, where P(t) is the percent of carbon-14 remaining, A0 is the initial amount (100%), t is age of the organism in years, and H is the half-life.

 

A. P(t) = 100(0.5)t/5,730, 3% remaining 

B. P(t) = 100(0.5)5,730t, 19% remaining 

C. P(t) = 5,730(0.5)100/t, 5,717 remaining 

D. P(t) = 100(0.5)5,730/t, 97% remaining

 Feb 22, 2016
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The amount remaining =

 

A0(0.5)^(30000/5730)=

 

A0 * (0.0265)  =   

 

About 3%

 

A is correct

 

 

cool cool cool

 Feb 22, 2016

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