Suppose we have a bag with 10 slips of paper in it. Eight slips have a 3 on them and the other two have a 9 on them.
How many 9's do we have to add to make the expected value equal to 6?
Suppose we have a bag with 10 slips of paper in it. Eight slips have a 3 on them and the other two have a 9 on them.
How many 9's do we have to add before the expected value is at least 8?
Suppose we have a bag with 10 slips of paper in it. Eight slips have a 3 on them and the other two have a 9 on them.
What is the expected value of the number shown if we add one additional 9 to the bag?
I will give the first one a try and you do the other 2:
3 x 8 =24
2 x 9 =18
24 + 18 =42
To get expected value of 6, we should have:
6 x N =96
96 - 42 =54
54 / 9 =6 "nines" have to be added to the 10 slips of paper to get 16 slips.
[8 x 3] + [8 x 9] =24 + 72 =96
96 / 16 slips of paper =6 - the expected value.
