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Suppose we have a bag with 10 slips of paper in it. Eight slips have a 3 on them and the other two have a 9 on them.
How many 9's do we have to add to make the expected value equal to 6?

 

Suppose we have a bag with 10 slips of paper in it. Eight slips have a 3 on them and the other two have a 9 on them.
How many 9's do we have to add before the expected value is at least 8?

 

Suppose we have a bag with 10 slips of paper in it. Eight slips have a 3 on them and the other two have a 9 on them.
What is the expected value of the number shown if we add one additional 9 to the bag?

 
 Nov 20, 2022
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I will give the first one a try and you do the other 2:

 

3  x  8 =24

2  x  9 =18

24 + 18 =42

 

To get expected value of 6, we should have:

6  x  N =96

96  -  42 =54

54 / 9 =6 "nines" have to be added to the 10 slips of paper to get 16 slips.

 

[8  x  3] + [8  x  9] =24  +  72 =96

96 / 16 slips of paper =6 - the expected value.

 
 Nov 20, 2022

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