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-1
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avatar+82 

What is the $x$-coordinate of the point on the $x$-axis that is equidistant from points $A( -2, 0)$ and $B(0,4)$?

 Aug 21, 2023

Best Answer 

 #2
avatar+128398 
+1

Let the point we are  seeking  be (x , 0)

 

Simplifying from  the  distance  formula, we  have

 

(-2 - x)^2  =  x^2 +  4^2 

 

x^2 + 4x + 4  = x^2 + 16

 

4x =  12

 

x = 3

 

cool cool cool

 Aug 22, 2023
 #1
avatar
0

Let the point on the x-axis be (x,0). Since this point is equidistant from A and B, we have

[\sqrt{(x + 2)^2 + 0^2} = \sqrt{(x - 0)^2 + 4^2}]or (x+2)2=x2+16. Solving, we find x=−1​.

 Aug 21, 2023
 #2
avatar+128398 
+1
Best Answer

Let the point we are  seeking  be (x , 0)

 

Simplifying from  the  distance  formula, we  have

 

(-2 - x)^2  =  x^2 +  4^2 

 

x^2 + 4x + 4  = x^2 + 16

 

4x =  12

 

x = 3

 

cool cool cool

CPhill Aug 22, 2023

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